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7x/4x+3-10x+6/4x+3=-3x+12x^2/(4x+3)(4x-3)
We move all terms to the left:
7x/4x+3-10x+6/4x+3-(-3x+12x^2/(4x+3)(4x-3))=0
Domain of the equation: (4x+3)(4x-3))!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-(-3x+12x^2/(4x+3)(4x-3))-10x+7x/4x+6/4x+6=0
We use the square of the difference formula
16x^2-10x+7x/4x+6/4x+9+6=0
We multiply all the terms by the denominator
16x^2*4x-10x*4x+7x+9*4x+6*4x+6=0
We add all the numbers together, and all the variables
16x^2*4x+7x-10x*4x+9*4x+6*4x+6=0
Wy multiply elements
64x^3-40x^2+7x+36x+24x+6=0
We do not support expression: x^3
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